unordered_list template filter fails for certain sequences

[Noam]

unordered_list consumes it's input by pairs. When given a sequence that contains at an even position two strings and then a list (such as ['a', 'a', ['b']]), it will consume both strings and treat the list as an item on it's own, and not as a sublist of the second string.

The result:

>>> from django.template import defaultfilters
>>> print str(defaultfilters.unordered_list(['a', 'a', ['b']]))
	<li>a</li>
	<li>a</li>
	<li>[&#39;b&#39;]</li>

See pull request with a test and a fix:
​https://github.com/django/django/pull/4917

[Tim Graham]

Regression in b3660d28f3422a33a84de7a7ccad404b3135a1a8

[Tim Graham <timograham@…>]

In e291fc4:

Fixed #25031 -- Fixed a regression in the unordered_list template filter.

[Tim Graham <timograham@…>]

In fd61ce38:

[1.8.x] Fixed #25031 -- Fixed a regression in the unordered_list template filter.

Backport of e291fc4757e952fd4f663d88adca416b016db13e from master

[msimonds]

This is still causing me trouble.

[Tim Graham]

Please open a new ticket with steps to reproduce the issue, thanks.