Opened 13 years ago
Closed 13 years ago
#18463 closed Bug (fixed)
Using len() in Paginator object can raise an error
Reported by: | Owned by: | Claude Paroz | |
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Component: | Core (Other) | Version: | dev |
Severity: | Normal | Keywords: | |
Cc: | Triage Stage: | Accepted | |
Has patch: | no | Needs documentation: | no |
Needs tests: | no | Patch needs improvement: | no |
Easy pickings: | no | UI/UX: | no |
Description (last modified by )
I'm getting the following error if I try to run a piece of code through my views.py:
Traceback (most recent call last): File "<console>", line 1, in <module> File "/home/mp/webapps/django/rep/app/views.py", line 331, in search_species print len(recs) File "/home/mp/webapps/django/lib/python2.7/django/core/paginator.py", line 88, in __len__ return len(self.object_list) File "/home/mp/webapps/django/lib/python2.7/django/db/models/query.py", line 87, in __len__ self._result_cache = list(self.iterator()) File "/home/mp/webapps/django/lib/python2.7/django/db/models/query.py", line 284, in iterator model_cls = deferred_class_factory(self.model, skip) File "/home/mp/webapps/django/lib/python2.7/django/db/models/query_utils.py", line 180, in deferred_class_factory return type(name, (model,), overrides) TypeError: type() argument 1 must be string, not unicode
Strangely, if I run a similar code directly in the Django shell, everything goes well. The code looks like this:
from app.models import MyClass qs = MyClass.objects.all() from django.core.paginator import Paginator paginator = Paginator(qs, 25) recs = paginator.page(1) print len(recs)
So you have to run this code through a method in views.py to get a crash in the last line.
I'm afraid I have no idea of what's going on and how to properly fix this, but if I change the offending line from the traceback by forcing str() in the name parameter it works:
return type(str(name), (model,), overrides)
Change History (2)
comment:1 by , 13 years ago
Description: | modified (diff) |
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Owner: | changed from | to
Status: | new → assigned |
Triage Stage: | Unreviewed → Accepted |
comment:2 by , 13 years ago
Resolution: | → fixed |
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Status: | assigned → closed |
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This bug is only triggered when the model name in deferred_class_factory is truncated (> 80 chars) and then a Unicode string is returned. Calling str() seems a good solution.