#12965 closed (fixed)
unordered_list template filter fails when given a non-iterable second item in a two item list
| Reported by: | Graham Ullrich | Owned by: | nobody |
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| Component: | Template system | Version: | 1.2-beta |
| Severity: | Keywords: | ||
| Cc: | Triage Stage: | Ready for checkin | |
| Has patch: | yes | Needs documentation: | no |
| Needs tests: | no | Patch needs improvement: | no |
| Easy pickings: | no | UI/UX: | no |
Description
When unordered_list processes a list with just two items it fails if the second item is not iterable.
Once convert_old_style_list() determines that 'second_item' is not an empty list, it assumes that item is an iterable. That certainly is true for lists, tuples, and strings. However, if the second item is a non-iterable object the code doesn't work. Nothing in the documentation suggests that the unordered_list filter only accepts iterables, so I think this is a bug.
I've attached a patch with an associated test in regressiontests/defaultfilters/tests.py, but am unsure about whether a test is also needed in regressiontests/templates/filters.py.
Attachments (1)
Change History (4)
by , 15 years ago
| Attachment: | unordered_list.diff added |
|---|
comment:1 by , 15 years ago
| Triage Stage: | Unreviewed → Ready for checkin |
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comment:2 by , 14 years ago
| Resolution: | → fixed |
|---|---|
| Status: | new → closed |
comment:3 by , 14 years ago
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(In [13845]) Fixed #12965 - unordered_list template filter fails when given a non-iterable second item in a two item list
Thanks to grahamu for the report and patch.